2[x-4]=3[1+x]

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Solution for 2[x-4]=3[1+x] equation:


Simplifying
2[x + -4] = 3[1 + x]

Reorder the terms:
2[-4 + x] = 3[1 + x]
[-4 * 2 + x * 2] = 3[1 + x]
[-8 + 2x] = 3[1 + x]
-8 + 2x = [1 * 3 + x * 3]
-8 + 2x = [3 + 3x]

Solving
-8 + 2x = 3 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
-8 + 2x + -3x = 3 + 3x + -3x

Combine like terms: 2x + -3x = -1x
-8 + -1x = 3 + 3x + -3x

Combine like terms: 3x + -3x = 0
-8 + -1x = 3 + 0
-8 + -1x = 3

Add '8' to each side of the equation.
-8 + 8 + -1x = 3 + 8

Combine like terms: -8 + 8 = 0
0 + -1x = 3 + 8
-1x = 3 + 8

Combine like terms: 3 + 8 = 11
-1x = 11

Divide each side by '-1'.
x = -11

Simplifying
x = -11

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